Which could you use to prove triangle AED is congruent to triangle CEB?

Option (C)

Step-by-step explanation:

Given:

In right triangles ΔAED and CEB,

m∠AED = m∠CEB = 90°

DE ≅ BE

AD ≅ BC

To prove:

ΔAED ≅ ΔCEB

                    Statements                         Reasons

1). m∠AED = m∠BC = 90°              1). Given

2). DE = BE                                     2). Given

3). AD = BC                                    3). Given

4). ΔAED ≅ ΔCEB                          4). By HL theorem of congruence

Option (C) is the answer.

$8

step-by-step explanation:

it is pretty much backwards.

you take the 4x2 multiply that, and that is = $8

hit or miss i guess they never miss huh

step-by-step explanation:

you got a boyfriend i bet he doesnt kiss ya