The equation of a line parallel to line 3y - 2x = 9, passing through point P(6, 2) is
(a) y - 6 = }(x - 2)
(b) y - 2 = (x-6)
(c) y - 2 = }(x-6)
(d) y – 2 = } (x + 6)

The equation of the line is

y-2 = 2/3(x-6)

Step-by-step explanation:

The standard form of the straight line equation is;

y = mx + b

where m is slope

so ;

3y = 2x + 9

y = 2x/3 + 3

If two lines are parallel, then their slopes are equal

This mean that the slope of the line of the new equation is 2/3 too

Thus;

(y-2) = 2/3(x - 6)

3(y-2)= 2(x-6)

3y - 6 = 2x - 12

3y = 2x -12 + 6

3y = 2x - 6

its line 2 i just added the rest or else it wouldn't let me answer