What is the equation of the line perpendicular to Y= 2/3 X+ 1 that passes through the point (12, -6)? 3x + 2y = 24 O 3x + 2y = 6
O 2x - 3y = 42
O 2x – 3y = -48

what is the question?

step-by-step explanation:

c

step-by-step explanation:

there is vertical asymptote at x = 2 and x = 0

vertical asymptote occurs at the points where the denominator is 0. so we can say that

x = 2 occurs when there is a factor (x-2) in the denominator, and

x = 0 occurs when there is a factor "x" in the denominator

thus, the denominator of the equation would have "x * (x-2)", this is option c only. that's the correct answer.

step-by-step explanation: s