The weights of three kittens at one week old were 4.1 ounces, 3.5 ounces, and 3.4 ounces. If each kitten gained 2.5 ounces, how much would each of the kittens weigh? A 11 ounces B 6.6 ounces, 6 ounces, and 5.9 ounces C 1.6 ounces, 1 ounce, 0.9 ounces

B 6.6 ounces, 6 ounces, and 5.9 ounces

Step-by-step explanation:

First Kitten

Weighed: 4.1 ounces

Current weight => 4.1 ounces + 2.5 ounces

=>6.6 ounces

Second Kitten

Weighed: 3.5 ounces

Current weight => 3.5 ounces + 2.5 ounces

=>6 ounces

Third Kitten

Weighed: 3.4 ounces

Current weight => 3.4 ounces + 2.5 ounces

=> 5.9 ounces

Each of the kittens would weigh :

6.6 ounces, 6 ounces, and 5.9 ounces

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!