A bullet is fired straight up from a gun with initial velocity 1120 feet per second at an initial height of 8 feet. Use the formula h = − 16 t 2 + v 0 t + 8 to determine how many seconds it will take for the bullet to hit the ground. (That is, when will h = 0 ?) Round your answer to 2 decimal places

70 seconds

Step-by-step explanation:

Given that;

The initial velocity of the bullet fired = 1120 ft/s

Initial height h = 8 feet

The expression to determine how many seconds it takes the bullet to hit the ground is:

Thus;

Replacing the value of =  1120 and h = 0 (i.e. when h =0) in the above expression; we have:

= -16t² + 1120t + 8

mulitiply through by (-)

= 16t² -1120t - 8

Divide through by 8

= 2t² -  140t - 1

The above expression forms a quadratic equation.

where;

a = 2

b = -140

c = - 1

So, by using the quadratic formula , we have:

= 70

Thus, the time (in seconds) it took the bullet to it the ground = 70 seconds

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step-by-step explanation:

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