1. The probability of telesales representative making a sale on a customer call is 0.15. Find the probability that
(a) no sales are made in 10 calls
B)more than 1 sales are made in 20calls

a) the probability that  no sales are made in 10 calls is 0.1969

b) the probability more than 1 sales are made in 20calls is 0.8244

Step-by-step explanation:

Given that;

p = 0.15

q = 1 - p = 1 - 0.15 = 0.85

a) probability that  no sales are made in 10 calls will be;

n = 10

p(x=0) = ¹⁰C₀(0.15)⁰ (0.85)¹⁰ = 0.1969

Therefore the probability that  no sales are made in 10 calls is 0.1969

b) probability more than 1 sales are made in 20calls

n = 20

let y be number of sales in 20 calls

y∪Bin(n=20, p=0.15)

p(y > 1) = 1 - [p(y=0) + p(y=1)

= 1 - [²⁰C₀(0.15)⁰ (0.85)²⁰ + ²⁰C₁(0.15) (0.85)¹⁹] = 0.8244

Therefore the probability more than 1 sales are made in 20calls is 0.8244

i believe that the answer is

b. y-1=-2(x-4)

hope this !

lol.

it's ok we all do this sometimes.

-aparri