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Mathematics, 19.11.2020 23:40 Blazingangelkl

Eloise started to solve a radical equation in this way: Square root of negative 2x plus 1 βˆ’ 3 = x Square root of negative 2x plus 1 βˆ’ 3 + 3 = x + 3 Square root of negative 2x plus 1 = x + 3 Square root of negative 2x plus 1 βˆ’ 1 = x + 3 βˆ’ 1 Square root of negative 2 x = x + 2 ( Square root of negative 2 x )2 = (x βˆ’ 4)2 βˆ’2x = x2 βˆ’ 8x + 16 βˆ’2x + 2x = x2 + 8x + 16 + 2x 0 = x2 + 10x + 16 0 = (x + 2)(x + 8) x + 2 = 0 x + 8 = 0 x + 2 βˆ’ 2 = 0 βˆ’ 2 x + 8 βˆ’ 8 = 0 βˆ’ 8 x = βˆ’2 x = βˆ’8 Both solutions are extraneous because they don't satisfy the original equation. What error did Eloise make?

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Eloise started to solve a radical equation in this way: Square root of negative 2x plus 1 βˆ’ 3 = x Sq...
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