The area of a rectangular wall of a barm is 140 Square feet. its length is 6 feet longer than twice its
width. Find the length and width of the wall of the barn.

length = 20 feet

width = 7 feet

Step-by-step explanation:

This problem can be solved using a system of equations. Using the given information, you can formulate 2 equations:

l*w = 140

l = 2w + 6

In order to solve this system of equations, you can use the Substitution Property of equality to substitute the l in the first equation for (2w + 6) in order to find the width:

where l*w = 140 and l = 2w + 6,

1. (2w + 6)*w = 140

2. 2w^2 + 6w = 140

3. w^2 + 3w = 70

4. w^2 + 3w - 70 = 0

5. (w - 7) (w + 10) = 0

6. w = 7, -10

1. Substitution

2. Simplification

3. Divide both sides by 2

4. Subtract 70 from both sides

5. Factor the left side (find 2 numbers that add to 3 and multiply to -70)

6. Solve for w

The width must be 7 because a width of -10 is impossible. Now, you just need to plug that into the equation to solve for l:

l*w = 140

7l = 140

l = 20

That means that the length is 20 and the width is 7.

sorry i got nothing

step-by-step explanation: