Exterior angles of a triangle. Please help. Due today

1) 140 2)68 3) 125 4) 140

Step-by-step explanation:

for these, because you're trying to find the angle from 180 degrees, you would subtract the angle on the 180 degree line from 180.

1) 180-40 = 140

2) 180-112 = 68

3) 180-55 = 125

4) 180-40 = 140

Hope this helps!

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐