A red cross helicopter takes off from headquarters and flies 120 km at 45 degrees south of west. There it drops off some relief supplies, then flies 125 km at 20 degrees west of north to pick up three medics. If the helicoper then heads directly back to headquarters, find the distance and direction it should fly.

129.5km

9.78° North of east

Step-by-step explanation:

Let say HQ is at the origin (x = 0, y = 0)

the coordinates of the helicopter after the 1st flight can be expressed below as

X1= -120 cos45=84.85km

Y1= -120 sin45= -84.85km

its coordinate after the 2nd flight can be expressed as

X2= x1 - 125sin20

= -84.85-42.75

=-127.6km

Y2= y1- 125cos60

=-84.5+62.5

=-22km

The distance and it's direction for it to fly back to its HQ can be calculated as

S= √(22^2 + 127.6^2 )

=129.48km

Tan θ= y2/y1

=22/127.6= 0.1724

Tan-1(0.1724)

= 9.78° North of east

Hence, the distance and direction it should fly is 129.48km and 9.78° North of east respectively

lo.lll

step-by-step explanation:

30 miles

step-by-step explanation:

we know that 60 seconds equals 1 minute and 60 minutes 1 hour

44 ft       60 sec     60 min     158400   ft

  *   *   =

1 sec       1 min       1 hour         hour

we know that there are 5280 ft per mile

158400   ft       1 mile         30 miles

  *   =

1   hour               5280 ft     1 hour

so in 1 hour   it can travel 30 miles