SMART PEOPLE HELP I'll GIVE Todd draws a diagram using four identical right triangles to form a square as shown. Which BEST describes how to use the areas of the shaded triangles to begin a proof of the Pythagorean theorem?

(It does not come with a picture!!)

A. The side length of the white square is A, so the combined are of the four right triangles is C to the power of 2 mines A to the power of 2. This is equivilent to four times the area of each triangle. So, C to the power of 2 mines A to the power of 2 equals 4 (1/2 ab)

B. The side length of the white square is A, so the combined are of the four right triangles is C to the power of 2 mines A to the power of 2. This is equivalent to the area of each triangle. So, C to the ower of 2 mines A to the power of 2 equals 1/2ab

C. The side length of the white square is B - A, so the combined are of the four right triangles is C to the power of 2 mines ( B - A) to the power of 2. This is equivilent to four times the area of each triangle. So, C to the power of 2 mines (B - A) to the power of 2 equals 4 (1/2ab).

D. The side length of the white square is B - A, so the combined are of the four right triangles is C to the power of 2 mines B to the power of 2. This is equivalent to the area of each triangle. So, C to the power of 2 mines B to the power of 2 equals 1/2 ab.