An economist wants to estimate the mean per capita income (in thousands of dollars) for a major city in Texas. He believes that the mean income is $24.6, and the standard deviation is known to be $7.9. How large of a sample would be required in order to estimate the mean per capita income at the 80% level of confidence with an error of at most $0.56? Round your answer up to the next integer.

327

Step-by-step explanation:

Calculation for How large of a sample would be required in order to estimate the mean per capita income

First step is to find z 80% confidence level

At 80% confidence level the z will be:

α/2 = 1 - 80% = 1 - 0.80 = 0.20

α/2= 0.20 / 2 = 0.01

Zα/2= Z0.01= 1.28 from z table

Now let calculate the Sample size using this formula

Sample size = n= [( Zα/2* σ ) / E]^2

Let plug in the formula

n = (1.28*7.9/0.56)^2

n= 326.06

n=327 (Approximately)

Therefore How large of a sample would be required in order to estimate the mean per capita income will be 327

no this is a nonlinear negative

c.

step-by-step explanation:

because first you have to add the 4x, 9x, and the 7x together and you get 20x and then you add the last numbers up and you get 5and then you put the subtraction sign in there and that's how you get the answer.