Select the correct answer. Which point is a point where the graph of y= (x + 2)(x2 + 4x+3) crosses the x-axis?

A. (-3,0)

Step-by-step explanation: you have to set the equation y to zero and than calculate the x

--> (x + 2)(x2 + 4x+3) = 0

--> (x+2) = 0 and (x2 +4x + 3) =0

--> X = -2 and        D= (4² - 4*2*3) = 4

                                      X = (-4 + ) / 2 of  X = (-4 + ) / 2

                                       x= -1                         x=-3

answer: it's upside down and i can't read it

step-by-step explanation:

answer:

given the linear inequality :

add 2y to both sides we get;

simplify:

add 12 to both sides of an equation;

simplify:

divide both sides by 2 we get;

or

the related equation for the inequality equation [1] is;

y-intercepts defined as the graph crosses the y-axis.

substitute x =0 in [2] to solve for y;

y = 6

x-intercepts defined as the graph crosses the x-axis.

substitute value y = 0 to solve for x;

subtract 6 from both sides we get

multiply both sides by 2 we get;

or

x = -12

now, plot these point (0, 6) and (-12, 0) on graph as shown below and shade the graph below the solid line.