There is a dice game at the casino that costs $3 to play. A player rolls two dice. If the player gets a sum of 2 or 12 he or she gets back $28 (wins $25). If the person gets a 7, he or she gets back $5 (wins $2). If the player rolls anything other than a 2, 12, or 7 he or she gets nothing back (loses $3) How much would the player need to be charged to play the game in order to make this a fair game? (A fair game is one with an expected value of zero)

The answer would be a

The answer is 270 cars.you can do this by making a proportional relationship. for instance, 200 is the whole we are using, so on a “number line” 200 would be over 100%. now, since he sells 35% more, add 35% to 100% to get 135% on the other side of the “number line” on the bottom half, leaving the top half empty.cross multiply 200 by 135 then divide by 100 to get your answer. i hope this , if it did, , if you don’t mind, giving me brainiest! 200/100% } 200 • 135 /100 ? /135%