Find two consecutive integers such that ten more than twice the smaller is seven less than three times the larger.

1. which answer is the solution set to the given inequality? 2x+6< 8 a. x e (-∞,1) b. x e [1,∞) c. x e (1,∞) d. x e (-∞,1] 2. which answer represents the given compound inequality in interval notation? x≥12 or x< -4 a. x e [-4, 12) b. x e (-∞, -4) u [12,∞) c. x e (-∞, -4] u (12,∞) d. x e (-4,12] 3. which answer is the solution set of the given compound inequality? 7> x+6 or x-2≥3 a. x e (-∞, 1) u [5,∞) b. x e (1, 5] c. x e (-∞, 1) ∩ [5,∞) d. x e [1,5) 4. which conjunction or disconjunction is equivalent to the given absolute value inequality? |x+3|> 12 a. x+3> 12 and x+3< -12 b. x+3< 12 and x+3> -12 c. x+3< 12 or x+3> -12 d. x+3> 12 or x+3< -12