Solve 60=10√y-3

a. y= -39
b. y= 39
c. y= 39,-39
d. y= -10,39

60=10√(y-3)
60²=(10√(y-3))²
3600=100(y-3)
3600=100y-300
100y=3600+300
100y=3900
y=3900/100
y=39

we have to chek the possible
10√(39-3)=10√36=10(6)=60

B.  y=39

Rounding decimals is very similar to rounding other numbers. if the hundredths and thousandths places of a decimal is forty-nine or less, they are dropped and the tenths place does not change. for example, rounding 0.843 to the nearest tenth would give 0.8. , your welcome !