What is the point-slope form of a line that has a slope of -4 and passes through point (-3, 1) a. y-(-3) = -4(x-1)
b. y-1 = -4[x-(-3)]
c. -1-y1 = -4(-3-x1)
d. 3-y1 = -4(1-x1)

at home andrea has 1 2/3 kilograms of rice

step-by-step explanation:

0 is its x and y coordinate

let m = monomial

let t = trinomial

so, m times t = t.

monomial times a trinomial = another trinomial.

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

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