Two cars leave Denver at the same time and travel in opposite directions. One car travels 10 mi/h faster than the other car. The cars are 660 mi apart in 6 h. How fast is each car traveling? 40 mi/h and 50 mi/h
60 mi/h and 40 mi/h
60 mi/h and 70 mi/h
50 mi/h and 60 mi/h

50 mph and 60 mph

Step-by-step explanation:

Represent the two speeds by s and f (slower and faster).  Then f = s + 10.

We find the distance traveled by each car separately, sum up the absolute values of these distances and set this sum equal to 660:

(s + s + 10)(6 hr) = 660 mi.  Simplifying this, we get:

2s + 10 = 110, or

2s = 100.

Then s = 50 mph and f = (50 + 10) mph, or 50 and 60 mph (matches the last possible answer)

step-by-step explanation:

answer: option a.

step-by-step explanation:

you know that the quadrilateral opqr ( a four sided figure) is inscribed in circle. this means that all its vertices are on the circle.

then, by definition, the opposite angles of the quadrilateral are supplementary, this means that the sum of their measures is 180 degrees.

you can observe in the figure that the angles ∠opq   and the angle ∠orq   are opposite, therefore:

then, can be used to d to calculate the measure of ∠opq