Expand the brackets and simplify. a) 4(8 + 5) – 4g =
b) 6(p + 4) + 2(p - 12) =
c) 30 + 2(3z – 15) =
d) 204 + a) + a =
e) 6(a + 5) + 2(a – 7) =
f) 2(3 + w) + 5(2 + 6w) =

Zack notices that segment nm and segment pq are congruent in the image below: which step could him determine if δnmo ≅δpqr by sas? (5 points) segment mo ≅ segment qr segment on ≅ segment qp ∠ n ≅ ∠ r ∠ o ≅ ∠ q