1. The Sky Train from the terminal to the rental car and long-term parking center is supposed to arrive every 12 minutes. The waiting times for the train are known to follow a uniform distribution. What is the average waiting time (in minutes)?2. The Sky Train from the terminal to the rental car and long-term parking center is supposed to arrive every 16 minutes. The waiting times for the train are known to follow a uniform distribution. Find the 20th percentile for the waiting times (in minutes).3. The Sky Train from the terminal to the rental car and long-term parking center is supposed to arrive every 18 minutes. The waiting times for the train are known to follow a uniform distribution. What is the probability of waiting more than 16 minutes given a person has waited more than 9 minutes?

a

b

c

Step-by-step explanation:

Considering question 1

From the question we are told that  

   The waiting times for the train are known to follow a uniform distribution

i.e  

Generally the cumulative distribution function for uniform distribution is mathematically represented as

Generally the average time is mathematically represented as

=>    

=>    

Considering question 2

     The waiting times for the train are known to follow a uniform distribution

i.e  

Generally the 20th percentile of the waiting time is mathematically represented as

=>            

=>          

Considering question 3

        The waiting times for the train are known to follow a uniform distribution

i.e  

Generally the probability of waiting more than 16 minutes given a person has waited more than 9 minutes

=>    

=>      

=>      

no because mercury has a density of 13.6 grams per centimeter squared while gold has 19.32 grams centimeter squared

step-by-step explanation: