Mathematics, 18.11.2020 17:30 0140875
Suppose the radius of the cylinder is decreasing at a rate of 2 cm/sec, but the volume is constant. How fast is the height changing when the radius is 10 cm and the height is 35 cm? Include units with your answer. Hint: If the volume is constant, what do you know about the rate of change of the volume?
Answers: 3
![\frac{dv}{dt} = \pi [2r\frac{dr}{dt} h+ r^2 \frac{dh}{dt} ]](/tpl/images/0908/8506/279ee.png)
![0 = \pi [2 \pi h\frac{dr}{dt} + r^2 \frac{dh}{dt} ]](/tpl/images/0908/8506/5af3a.png)
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Suppose the radius of the cylinder is decreasing at a rate of 2 cm/sec, but the volume is constant....
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