How much money should be invested in an account that earns 8% interest compounded quarterly to yield $10,000 in 4 years? (Round your answer to the nearest cent.)

757,576cents

Step-by-step explanation:

Given

Amount = $10000

Time = 4years

Rate = 8%

n = 1/4 year (compounded quarterly

Using the formula to get the principal

A = P(1+r/n)^nt

10000 = P(1+0.08/0.25)^4(1/4)

10000 = P(1+0.32)

10000= 1.32P

P = 10000/1.32

P = 7575.76

Hence he suppose to invest $7575.76 which is equivalent to 7575.76×100 cents i.e 757,576cents

{x = -1/2 ,   y = -1

step-by-step explanation:

solve the following system:

{2 x + y = -2

{10 x - 3 y = -2

in the first equation, look to solve for y:

{2 x + y = -2

{10 x - 3 y = -2

subtract 2 x from both sides:

{y = -2 x - 2

{10 x - 3 y = -2

substitute y = -2 x - 2 into the second equation:

{y = -2 x - 2

{10 x - 3 (-2 x - 2) = -2

10 x - 3 (-2 x - 2) = (6 x + 6) + 10 x = 16 x + 6:

{y = -2 x - 2

{16 x + 6 = -2

in the second equation, look to solve for x:

{y = -2 x - 2

{16 x + 6 = -2

subtract 6 from both sides:

{y = -2 x - 2

{16 x = -8

divide both sides by 16:

{y = -2 x - 2

{x = -1/2

substitute x = -1/2 into the first equation:

{y = -1

{x = -1/2

collect results in alphabetical order:

answer:   {x = -1/2 ,   y = -1

25/14 or 1.

step-by-step explanation:

the dots mean that it has infinitely more numbers behind it