A(n)=−5+6(n−1)
I need to know what the 12th term in the sequence is.

61

Step-by-step explanation:

The formula of the sequence given is;

    aₙ = -5 + 6(n-1)  

problem is to find the 12th term;

   a₁₂  = -5 + 6 (12  - 1)

     a₁₂ = -5 + 6(11)

       a₁₂ = -5 + 66

        a₁₂ = 61

answer: was that a question or answer?

step-by-step explanation:

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐