Question 4 Titus is asked to prove hexagon FEDCBA is congruent to hexagon
F'E'D'C'B'A' in the graph below. Titus thinks that if he transforms hexagon
FEDCBA by (x, y) - (x + 16, y - 10) he can show the two figures are
congruent. Is he correct? Explain why or why not. If Titus is incorrect, what
series of transformations will correctly prove FEDCBA F'E'D'C' B'A'!
I need ASAP

No, Titus is incorrect.

Step-by-step explanation: Two shapes are congruent when they have the same size and shape, but one is created of rotation, reversion or translation of the other.

So, hexagons FEDCBA and F'E'D'C'B'A' are congruent because they have the same size and shape, however they are reversed and translated from each other, i.e.:

Comparing the coordinates of both hexagons:

F (-6,6) → F' (6, -4)

A (-10,6) → A' (10,-4)

E (-4,4) → E' (4, -6)

B (-12,4) → B' (12, -6)

D (-6,2) → D' (6, -8)

C (-10,2) → C' (10, -8)

We notice that the transformation necessary to transform FEDCBA into F'E'D'C'B'A' is

Therefore, it is (x,y) → ( -x, y-10).

So, Titus is incorrect about the transformations that prove the hexagons are congruent.

infinitely many solutions

step-by-step explanation:

we have been given the equation;

2(2x + 3) = -4 + 2(2x + 5)

we need to determine the value of x.

2(2x + 3), we expand this expression to obtain 4x + 6

similarly 2(2x + 5) will become 4x + 10

now we have;

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 10 - 4

4x + 6 = 4x + 6

the expression on the left hand side is identical to the one on the right hand side. therefore, we are looking at just a single straight line whose equation is;

y = 4x + 6

consequently, we shall have infinitely many solutions

10.416 m/s

step-by-step explantion:

distance=100m

time= 9.6s

average speed=100/9.6

=10.416 m/s