GIVEN: BA || CF, BC || ED. PROVE: angle 1 is congruent to angle 2

#11 please
20 points!!

∠1 ≅ ∠2 ⇒ proved down

Step-by-step explanation:

#11

In the given figure

∵ BA // CF

∵ BC is a transversal

∵ ∠1 and ∠BCF are interior alternate angles

∵ The interior alternate angles are equal in measures

∴ m∠1 = m∠BCF

∴ ∠1 ≅ ∠BCF ⇒ (1)

∵ BC // ED

∵ CF is a transversal

∵ ∠BCF and ∠2 are corresponding angles

∵ The corresponding angles are equal in measures

∴ m∠BCF = m∠2

∴ ∠BCF ≅ ∠2 ⇒ (2)

→ From (1) and (2)

∵ ∠1 and ∠2 are congruent to ∠BCF

∴ ∠1 and ∠2 are congruent

∴ ∠1 ≅ ∠2 ⇒ proved

a: 1/6, j: 1/4

step-by-step explanation: you are welcome