A comer store sells two kinds of baked goods: cakes and pies. A cake costs $8 and a pie costs $11. In one day, the store sold 11 baked goods for a total of $112. How many cakes did they sell?
a. 3 cakes
c. 2 cakes
b 11 cakes
d. 8 cakes

8  number of cakes were sold.

Step-by-step explanation:

Out of 12 baked goods sold , let the number of cakes sold be x in number and pies sold were 12 − x in number. Total sell was $ 144 , 1 cake costs $ 14 and 1 pie costs $ 8 ∴ 14 ⋅ x + ( 12 − x ) ⋅ 8 = 144 or 14 x − 8 x = 144 − 96 or 6 x = 48 ∴ x = 8 Therefore, 8 cakes were sold [Ans]

3 cakes

Step-by-step explanation:

3x8=24

112-24=88

88/11=8

3cakes +8 pies= 11 baked goods

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.