PLEASE HELP ASAP IM TIMED A researcher is 95% confident that the interval from 19.8 to 31.5 captures = the true mean number of unbroken crackers in a certain-sized bag.
Is it plausible that the true mean number of unbroken crackers for all bags of this size may be 30?
O No, this is not a plausible value for the population mean, because 30 is within the 95% confidence interval
O No, this is not a plausible value for the population mean, because 30 is not within the 95% confidence interval.
Yes, this is a plausible value for the population mean, because 30 is within the 95% confidence interval.
O Yes, this is a plausible value for the population mean, because 30 is not within the 95% confidence interval.

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)

isaiah walks 3 miles due north, turns and then 5 miles due east. how far is he from his starting point?

a^2 + b^2 = c^2

let c = distance from starting point.

(3)^2 + (5)^2 = c^2

9 + 25 = c^2

34 = c^2

sqrt{34} = sqrt{c^2}

sqrt{34} = c