Please show me the steps to solve this problem

This is a pre-algebra problem. I'll go through the steps with you. If you don't get it, don't be afraid to ask!

Step One - Cross Multiply

These are fractions, but that doesn't mean you have to add them. Fractions are just the numerator divided by the denominator. So to 'remove' the 9, multiply both sides by 9. To 'remove' the 6, multiply both sides by 6. (We multiply both sides of the equation by the same number because we need to make each side the same). Note that when you multiply both sides by 9 or 6, you have to multiply the whole part.

(2x+1)×6 = (1-1)×9

Distribute.

12x+6 = 9-9

Step Two - Solve the Equation

So we are left with this equation after cross multiplying:

12x+6 = 9-9

First, we can start by subtracting 9 from 9, because those are the same types of numbers.

12x+6 = 0

Now, we have to 'remove' the 6. We can do that by subtracting each side by 6.

(12x+6)-6 = 0-6

12x = -6

Now we are left this this.

We need to 'remove' the 12 now, so we can isolate the x. Since 12 is multiplied to x, we divide each side by 12.

(12x)÷12 = -6÷12

We get x = -1/2

x = -1/2 or -0.5

Hope this helped!

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