A rectangular yard measuring 39ft by 63ft is bordered (and surrounded) by a 2 ft fence. Inside, a walk that is wide goes all the way along the fence. Find the area of this walk. Be sure to include the correct unit in your answer.

Given :

A rectangular yard measuring 39 ft by 63 ft is bordered (and surrounded) by a 2 ft fence.

To Find :

The area of this walk.

Solution :

Area of whole park :

Now, length and breadth after removing the fences is l = 63 - 2( 2) = 59 ft and b = 39 - 2( 2 ) = 35 ft.

Area of inner park :

A' = 35 × 59 ft²

A' = 2065 ft²

Therefore, area of fencing is 2457 - 2065 = 392 ft² .

Hence, this is the required solution.

there are 70 more legs than eyes at the dog show (196 – 126 = 70). dogs have two more legs than eyes, and humans have the same number of legs as eyes. thus 70 is twice the number of dogs at the show, so the number of dogs is half of 70, which is 35. to get the number of humans, subtract 35 from 63: 63 – 35 = 28.

step-by-step explanation: