Perpendicular to the line 4x - 6y + 7 = 0 , passing through (3, 4) .

The equation of line perpendicular to given line passing through (3,4) is:

Step-by-step explanation:

Given equation of line is:

Given equation is in standard form. It has to be converted into slope-intercept form to extract slope from the equation.

So,

The standard form of slope-intercept form of equation is:

Here, the co-efficient of x is the slope of the line.

So the slope of given line is: 2/3

m = 2/3

The product of slopes of two perpendicular lines is -1

Let m1 be the slope of line perpendicular to given line

Then

The equation of perpendicular will be:

Putting the value of slope

To find the value of b, putting (3,4) in the equation

So the equation of line perpendicular to given line passing through (3,4) is:

∠acb = 8°

step-by-step explanation:

∠xba lies on the circle and is half the measure of the intercepted arc ax

hence

measure of arc ax = 2 × 42° = 84°

∠acb is outside the circle and is

∠acb = (arcab - arcax ), hence

∠acb = 0.5 (100 - 84) = 0.5 × 16° = 8°