Please help me out ASAP!
Picture below. Thank you in advance!

If h(x) = f[tex]h(x) = f[/tex] ° [tex]g) (x)[/tex] and [tex]h(x) = \sqrt[3]{x+3}[/tex], find [tex]g(x)[/tex] if [tex]f(x) = \sqrt[3]{x +2}[/tex] ·

Refer to the table below if needed. second quadrant third quadrant fourth quadrant sin(1800- - cos(180° -) tan(180°-e) =- tane cot(1800-0) 10 it to solo 888 sin(180° +c) = - sine cos(180° +) =- cose tan(180° +c) = tane cot(180° +o) = cote sec(180° + c) = - seco csc(180° +2) = - csce sin(360° -) =- sine cos(360° -) = cose tan(360° - e) =- tane cot(360° -) = -cote sec(360° -) = seco csc(360° -) = csco sec(180° -) = csc(180° -) = csca 1991 given that sine = 3/5 and lies in quadrant ii, find the following value. tane

Based on the graph, what is the initial value of the linear relationship? a coordinate plane is shown. a line passes through the y-axis at -2 and the x-axis at 3.