What is an equation of the line that passes through the points (0, - 5) and (- 6, 0) ? Put your answer in fully reduced form.

y= mx + b

y= - 5/6x + b

slope is 1

y-intercept is (0,-5x/6)

Step-by-step explanation:

(0, -5) (-6, 0)

y2 -y1 =  0- -5 =  5

x2-x1  =  -6- 0=    6

-5/6

the value of v.w= -12.

step-by-step explanation:

we are given three vector r,v and w as:

r = < 5, -5, -2> ; v = < 2, -8, -8> ; w = < -2, 6, -5>

we know that r,v and w could also be represented as:

r=5i-5j-2k

v=2i-8j-8k

and w= -2i+6j-5k

where i,j and k are the unit vectors of x,y and z-axis respectively.

also we know that it has the following property:

i.i=1 ; j.j=1; k.k=1

and i.=j.i=i.k=k.i=j.k=k.j=0

i.e. when we multiply two vectors or we find it's dot product we need to only multiply the components of x coordinates with each other; y with each other and z with each other.

hence, v.w= (2i-8j- -2i+6j-5k)

                  = 2×(-2)+(-8)×(6)+(-8)×(-5)

                  = -4-48+40

                  = -12

hence, v.w= -12

im alright what do you need

step-by-step explanation: