Twenty years ago, % of parents of children in high school felt it was a serious problem that high school students were not being taught enough math and science. A recent survey found that of parents of children in high school felt it was a serious problem that high school students were not being taught enough math and science. Do parents feel differently today than they did twenty years ago? Use the level of significance. Because
nothing
▼
equals
less than
not equals
greater than
10, the sample size is
▼
greater than
less than
5% of the population size, and the sample
▼
cannot be reasonably assumed to be random,
can be reasonably assumed to be random,
is given to not be random,
is given to be random,
the requirements for testing the hypothesis
▼
are
are not
satisfied.
(Round to one decimal place as needed.)

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.

details

step-by-step explanation:

hard

step-by-step explanation: