A waterfall has a height of 1700 feet. A pebble is thrown upward from the top of the falls with an initial velocity of  feet per second. The height of the pebble h in feet after t seconds is given by the equation h=-16t^2+24t+1700 . How long after the pebble is thrown will it hit the ground? PLEASE HEL

Step-by-step explanation:

The expression is given as:

Required

Determine how long it will hit the ground

When the pebble is on the ground, this implies that h = 0

So, we have that:

becomes

Reorder

Multiply through by -1

Solve using quadratic formula :

Where

So, we have:

or

or

or

But time can't be negative.

So:

Hence, it will take 11.085 seconds to hit the ground

the height of the surface increases from the center out to the sides of the road.

step-by-step explanation:

as we move out we move away from the x-axis.

and as mentioned in the problem statement that height of a road increases when we move away from the center x.

hence proved that 3rd option

the height of the surface increases from the center out to the sides of the road.

is the correct option.

you estimate that the angle of elevation to the top of the 86th floor (the observatory) is 82 .the total height of the building is another 123 meters above the 86th floor.

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