Identify the x-intercept and the y-intercept of the graph of 6x + 15y = −30.

x=

−5

2

y−5

explanation:Let's solve for x.

6x+15y=−30

Step 1: Add -15y to both sides.

6x+15y+−15y=−30+−15y

6x=−15y−30

Step 2: Divide both sides by 6.

6x

6

=

−15y−30

6

x=

−5

2

y−5

3.76%

step-by-step explanation:

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐