3x4 + 20x3 + 14x2 + 170 + 30 and x + 6?

the correct answers i think are b. and d.

give me brainliest if it is correct!

  b:   ∠x = 28.6°, ∠y = 31.2°, ∠z = 120.2°

step-by-step explanation:

this is one of those questions where "test taking skill" is all you need. the only answer that has angles that sum to 180° is the one shown above. the remaining choices do not describe the angles of a triangle.

if you want to do more work than simply adding the offered numbers, you can also check them against the law of sines. it should be true that

  x/sin(x) = y/sin(y) = z/sin(z)

and all of these ratios must be greater than 15, the longest side length.

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if you want to solve the triangle from scratch, i'd suggest solving for the largest angle using the law of cosines.

  z² = x² +y² -2xy·cos(z)

  z = arccos((x² +y² -z²)/(2xy)) = arccos(-75.11/149.4) = 120.182°

now you can find y from the law of sines

  y = arcsin(y/z·sin(z)) = 31.242°

if a polygon ab c d e is transformed to congruent polygon mn o p q, then following possibilities can happen

1. rotation                 2. reflection             3. translation   4. reflection and then translation or vice versa     5. rotation and then reflection or vice versa     6. translation and rotation   or vice versa   7. all of three , rotation, then reflection and then translation or in any order.  

we will get a congruent polygon m n o p q which is congruent to a b c de.

now , polygon   m n o p q is translated 3 units right and 5 units down to get a   congruent polygon, v w x y z, so if vertices of   polygon   m n o p q is m(x,y), n(u,v), o(p,q), p(r,s) and   q(a,b)   this, then vertices of polygon, v w x y z will be ,v(x+3,y-5), w(u+3,v-5),o(p+3,q-5),p(r+3,s-5),q(a+3,b-5).