Which of these is a linear equation in
standard form for the graph shown?

B

Step-by-step explanation:

Because the slope is a positive slope (goes through the positive quandrants on the graph), we can eliminate answer choices c. Now, if we solve a, b, and d and we can see if the slope + y-intercept matches the graph.

For A.) (solve for y to get a y=mx + b equation)

3x-2y=4

-2y= -3x + 4

y= 3/2 -2

For B.)

3x-2y= -4

-2y= -4-3x

y= 3/2 + 2

For D.)

2x+3y= 4

3y= 4-2x

y= -2/3x + 4/3

Now, if we look at D, the slope is negative so it cannot be D. That leaves us with A and B. The b in the y=mx + b equation stands for the y-intercept, so we can see that the y-intercept is 2. So, since the graph intersects the y-axis at (0,2), the answer is B! y=3/2 + 2 has a positive slope and 2 for the y-intercept!

-6 is the correct option from the above given options

so, converting firstly the mixed fractions to improper fractions and then "adding".