`PLSS PLSSS HELPPP I WILL GIVE BRAINLIEST PLSSS HELPPP I WILL GIVE BRAINLIEST
PLSSS HELPPP I WILL GIVE BRAINLIEST

question is the picture ofc

AB = DE

BC = EF

CA = FD

Angle A = Angle D

Angle B = Angle E

Angle C = Angle F

(Of course Angle A is short for angle BAC, etc.)

If in triangles ABC and DEF, AB = DE, AC = DF, and angle A = angle D, then triangle ABC is congruent to triangle DEF.

Step-by-step explanation:

Again, one can make congruent copies of each triangle so that the copies share a side. Then one can see that AC must = DF.SSA would mean for example, that in triangles ABC and DEF, angle A = angle D, AB = DE, and BC = EF.

With these assumptions it is not true that triangle ABC is congruent to triangle DEF. In general there are two sets of congruent triangles with the same SSA data.

two data sets with the same median will not have the same varaibility

step-by-step explanation:

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