Consider the equation 3a+0.1n=123. If we solve this equation for n, which equation would result? A. 0.1n=123-3a B. N=123-3a-0.1 C. N=1,230-30a D. 3a-123 over 0.1 =n

n = (123 - 3a) / 0.1

Step-by-step explanation:

Given:

3a + 0.1n = 123

Solve for n

3a + 0.1n = 123

Subtract 3a from both sides

3a + 0.1n - 3a = 123 - 3a

0.1n = 123 - 3a

Divide both sides by 0.1

n = (123 - 3a) / 0.1

The resulting equation if 3a + 0.1n = 123 is solved for n is n = (123 - 3a) / 0.1

a. the are of the rectangle is 18.25

b. 18.25 times two is 36.50

rae me : d

hello from mrbilldoesmath!

answer:

x - 3

discussion:

x^2 - 9 = (x-3) (x+3)   so

(x^2-9)/ (x + 3) = x-3

you,

mrb