please help :,) identify an equation in slope-intercept form for the line parallel to y=3x+5 that passes through (4,-1)

A. y + 1 = -3(x - 4)

Step-by-step explanation:

If the equations are perpendicular, then that means they have the same slope, just with the opposite sign. In this case, the given equation's slope is 3, which means that the other equation's slope is -3. Now that we know the slope and one point, we can write the equation in point-slope form:

y - y1 = m(x - x1)

y - (-1) = -3(x - 4)

y + 1 = -3(x - 4)

The equation in point-slope form is answer choice A. y + 1 = -3(x - 4).

Hope this helps :)

california, bc u would have lots of freedom there.

we have been given a piecewise function which has three parts

we can graph each part one by one.

first part is x+1 which is just like equation y=x+1

restriction with first part is x< 0 so that means we can use any number for x which is less than 0 for example x=-1 and x=-2

now plug x=-1 into y=x+1 to get y

y=x+1=-1+1=0

so the point will be (-1,0)

similarly we get another point (-2,-1)

now we graph a line joining both points but keep in mind that line must be on left side of x=0 because of restriction x< 0

same way we can graph 2nd and third parts

if we have < or > then we use open circle.

if we have < = or > = then we use close circle.

so using above information, final graph can be drawn as: