Find the slope (m) and y -intercept (b) of the equation in standar form 2x-3y=6

m = , b = - 2

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + b ( m is the slope and b the y- intercept )

Given

2x - 3y = 6 ( subtract 2x from both sides )

- 3y = - 2x + 6 ( divide all terms by - 3 )

y = x - 2 ← in slope- intercept form

with slope m = and y- intercept b = - 2

y- intercept is (0, -2)

slope is 2/3

Step-by-step explanation:

find 2 points on the line:

2x-3y=6

1/2*(6+3y) =x

if y is 2, x is 6 ((6,2))

if y is 4, x is 9 ((9, 4))

y-intercept is when x = 0.

0-3y=6

y=-2

slope is (y2-y1)/(x2-x1): choose y2 and the corresponding x-coordinate is x2. then the others are the 1's. let's use 4 as y2 which means:

x2 = 9

x1 = 6

y1 = 2

then plug in and solve.

(4-2)/(9-6)

= 2/3

m = 2/3

Hope this helps!

i dont know

step-by-step explanation:

step-by-step explanation:

first, eliminate the parenthesis:

3

x

+

2

−

4

x

second, group like terms:

3

x

−

4

x

+

2

third, combine like terms:

(

3

−

4

)

x

+

2

→

−

1

x

+

2

→

−

x

+

2