Using the feasible region below, determine which x and y values will maximize the profit, P, in the equation P = 40x + 55y * 1 point A(0, 500)
B(300, 400)
C(380, 200)
D(400, 0)
E None of the Above

B (300, 400)

Step-by-step explanation:

The profit maximization will be when the sum of the products will be greater. The maximum profit will be when x is 300 and y is 400. If we put in the equation :

P = 40x + 55 y

A - When x =  0 , y = 500

P = [40 * 0] + [55 * 500]

P = 27500

B -

When x =  300 , y = 400

P = [40 * 300] + [55 * 400]

P = 34000

C -

When x =  380 , y = 200

P = [40 * 380] + [55 * 200]

P = 26200

D -

When x =  400 , y = 0

P = [40 * 400] + [55 * 400]

P = 16000

see below

step-by-step explanation:

7.   there are 10 data points in the set.   the middle point is between 5 and 6.   the middle point in the top half is 8   and the middle point in the bottom half is 3. to find the iqr , take point 8 and subtract point 3

mid term   point 8 = 100   point 3 = 88

iqr = 100-88 = 12

final   point 8 = 93   point 3 = 78

iqr = 93 - 78 = 15

the final has the greatest iqr

6.   b - there is a high data value that causes the data set to be asymmetrical for the males: the data for males are high and asymmetrical .   there is an outlier for the males that skews the data

5.   the   iqr is a better measure of spread for the movies and basketball games.   since the basketball game has an outlier, we do not want to use standard deviation for measurement.  

3.   the exam median is much higher than the class median.   the median line is farther to the right on the exams

2.   there is no way to tell what the means are from the box and whisker plots.  

if a = 1,   and b = 2, then the answer is 47.99999999. if you round that to the nearest whole number, the answer is 48.