at a basketball game at team made 58 successful shots they were a combination of one and two point shots the team scored 98 points in all right and solve a system of equations to find out the number of each type of shot

There were 18 1 point goals and 40 2 point goals

Step-by-step explanation:

Let the number of one point shots be x and the number of two point shots be y

Total number of shot is 58

x + y = 58 ••••(i)

Then;

Total of 1 point is 1 * x = x

Total of 2 points is 2 * y = 2y

x + 2y = 98 ••••••(ii)

x = 98-2y

Put this in 1

98-2y + y = 58

-y = 58-98

y = 40

x = 58-40

x = 18

answer: idk

step-by-step explanation:

your answer is -9

step-by-step explanation: