The sum of a number and twice another number is 17. The sum of twice the first number and the second number is 4. What are the two numbers? a) define the variables

b) write a system of equations

c) solve by elimination

Step-by-step explanation:

Given that,

a + 2b = 17

Also,

2a + b = 4

By adding the above expressions we get,

a + 2b + 2a + b = 17 + 4

3a + 3b = 21.

3 (a + b) = 21

a + b = 21/3

a + b = 7 Let us take 'b' = 10

a + 10 = 7

a = 7 - 10

a = -3

Now let's check by verifying by putting a = -3 and b = 10 in the previous expressions

a + 2b = 17

-3 + (2 × 10) = 17

-3 + 20 = 17

17 = 17

2a + b = 4

(2 × -3) + 10 = 4

-6 + 10 = 4

4 = 4

Therefore, a = -3 and b = 10 [(-3,10)] is the solution.

the answer is 844

step-by-step explanation:

it is 844 because if you add 836.50 + 7.5 you will get 844

its an acute right triangle

step-by-step explanation: