What is the equation of the line that passes through the point (2,-4) and has a slope of 2

2x - y - 8 = 0

Step-by-step explanation:

x1 = 2

y1 = -4

m = 2

using the formula,

y-y1 = m(x-x1)

y+4 = 2(x-2)

y+4 = 2x - 4

y-2x+4+4 = 0

y-2x+8 = 0 (×-1)

2x - y - 8 = 0

Therefore the equation of the line is;

2x-y-8 = 0

where is abdul's work? don't see that anywhere posted : /

step-by-step explanation:

correct answer was 0.5