Olve the system of inequalities: y + 2x > 3 and y Greater-than-or-equal-to 3.5x − 5 The first inequality, y + 2x > 3, is
y > –2x + 3
in slope-intercept form.

The first inequality, y + 2x > 3, has a
dashed
boundary line.

The second inequality, y Greater-than-or-equal-to 3.5x − 5, has a
dashed
boundary line.

Both inequalities have a solution set that is shaded
their boundary lines.

is a point in the solution set of the system of inequalities.

look at the picture.

y-intercept for the function on a picture is 4 → point (0, 4).

y-intercept for the function

is for x = 0. substitute:

y-intercept is 8 → point (0, 8).

answer:   the paragraph proof is mentioned below.

step-by-step explanation:

given: in a δxwy where

such that, ∠wzx ≅ ∠yzx and zw≅zy

we have to prove that: segment zx is a perpendicular bisector of segment wy.

prove: since, zw≅zy ⇒ ∠wzy is a supplementary angle.

then, ∠wzy= 180°

⇒∠wzx + ∠yzx = 180° ( because xz divides ∠wzy into two parts)

but, ∠wzx ≅ ∠yzx ( given)

⇒∠wzy+∠wzy=180° ( by substitution)

⇒2∠wzy=180°

⇒∠wzy=90°

⇒∠wzy=∠yzx =90°

therefore, xz⊥wy where wz=zy

⇒zx is a perpendicular bisector of wy.