Let f(x)=2x^4+x^3+x^2-3x+r. For what value of r is f(2)=0?

the answer is 0

Step-by-step explanation:

r = -38

Step-by-step explanation:

For what value of r in the formula:  f(x)  =  2x4 + x3 + x2- 3x + r  does  f(2)  =  0?

Replace x with 2:  2·24 + 23 + 22- 3·2 + r  =  32 + 8 + 4 - 6 + r  =  38 + r

This value is to equal 0:   38 + r  =  0

                                                r  =  -38

-14 is the answer

hope this : ))