Is it possible that there exists some function g(x) and some constant L such that lim┬(x→2^+ )⁡〖g(x)〗=lim┬(x→2^- )⁡〖g(x)〗=L, but lim┬(x→2)⁡〖g(x)〗 does not exist? If so, draw a sketch of such a function. If no, explain why not.

a) t'(-3, 6) and v'(0, 3)  

step-by-step explanation:

hope it

step-by-step explanation:

x^(1/6) · x^(1/6) · x^(1/6)   ·x^(1/6) = x^(4/6)   since we add the exponents

4/6 can be simplified to 2/3

the simplified form is x^(2/3)

correct choice is a

step-by-step explanation:

the equation of the line passing through the points and is

thus, the equation of the line that passes through the points (0, -6) and (-3, 0) is

i will with my problems and all the other things that need to   be on by the way

step-by-step explanation: