Please help 30 points!!' Write an equation based on the following conditions in slope/y intercept form
Perpendicular to 3x-4y=9 through (-15,-4)
also can yall provide some shown work as my geometry teacher asked for shown work

The equation of line perpendicular to given line passing through (-15,-4) is:

Step-by-step explanation:

Given equation is:

The given equation is in standard form. We have to convert it into slope intercept form first.

The slope intercept form is:

So,

The co-efficient of x is the slope of the line.

m = 3/4

The product of slopes of two perpendicular lines is: -1

Let m1 be the slope of line perpendicular to given line then

Putting in slope-intercept form

To find the value of b, putting (-15,-4) in equation

The equation will be:

Hence,

The equation of line perpendicular to given line passing through (-15,-4) is:

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°

can you rephrase the question ? it is unclear : -)

step-by-step explanation: