PLEASE HELP 2. Toss 4 times Imagine tossing a fair coin 4 times . (a ) Give a probability model for this chance process . (b) Define event B as getting exactly three tails . Find P(B)

If a coin is tossed 4 times; number of possible outcomes = (2^4) = 16. 3 heads and 1 tail can occur from 4 tosses in (4C3)*(1C1) = 4*1 = 4 ways. So, the probability = (4 / 16) = (1 / 4) = 0.25.  

i didnt really understand the question but hope this helps

use the power rule  

( a b ) n = a n b n

to distribute the exponent.

apply the product rule to  

3 x 2 y 3 . ( 3 x 2 ) 2 ( y 3 ) 2

apply the product rule to  

3 x 2 . 3 2 ( x 2 ) 2 ( y 3 ) 2

raise  

3

to the power of  

2 . 9 ( x 2 ) 2 ( y 3 ) 2 multiply the exponents in   ( x 2 ) 2

.

apply the power rule and multiply exponents,  

( a m ) n = a m n . 9 x 2 ⋅ 2 ( y 3 ) 2

multiply  

2   by   2 . 9 x 4 ( y 3 ) 2

multiply the exponents in  

( y 3 ) 2 .

apply the power rule and multiply exponents,  

( a m ) n = a m n . 9 x 4 y 3

⋅

2

multiply  

3   by   2 . 9 x 4 y 6

step-by-step explanation:

step-by-step explanation :

we know that

the measurement of the outer angle is the semi-difference of the arcs which comprises

in this problem

m< xzy is the outer angle

substitute the values

the measure of angle xoy is equal to

> by central angle

substitute the value